If θ≥ð3n þ 7Þ=ð2n þ 4Þ then gðxÞ ≤θ is satisfy over (0,1], which means translation - If θ≥ð3n þ 7Þ=ð2n þ 4Þ then gðxÞ ≤θ is satisfy over (0,1], which means Thai how to say

If θ≥ð3n þ 7Þ=ð2n þ 4Þ then gðxÞ ≤θ

If θ≥ð3n þ 7Þ=ð2n þ 4Þ then gðxÞ ≤θ is satisfy over (0,1], which
means that x ≤ðpx −cÞ=ðhEÞ is redundant (see Fig. 2(a)).

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Results (Thai) 1: [Copy]
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ถ้า θ≥ð3n þ 7Þ = ð2n þ 4Þ แล้ว gðxÞ ≤θคือการตอบสนองมากกว่า (0,1], ซึ่ง หมายความ ว่า −cÞ x ≤ðpx = ðhEÞ เป็นซ้ำซ้อน (ดู Fig. 2(a))
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Results (Thai) 2:[Copy]
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หากθ≥ð3nþ 7 = ð2nþที่ 4 แล้วgðxÞ≤θคือความพึงพอใจมากกว่า (0,1]
ซึ่งหมายความว่าx = ≤ðpx-cÞðhEÞซ้ำซ้อน (ดูรูป. 2 (ก))

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Results (Thai) 3:[Copy]
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ถ้าθ≥ð 3N þ 7 Þ = ð 2n þ 4 Þแล้ว G ð x Þ≤θพึงพอใจมากกว่า ( 0.1 ] ซึ่งแปลว่า X
≤ð PX − C Þ = ðเขาÞซ้ําซ้อน ( ดูรูปที่ 2 (

) )
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