If G’(j) is not determined in the f

If G’(j) is not determined in the first scan and 1

Results (English) 1:

If G ' (j) is not determined in the first scan and 1< = j< = f ' (k ') (1)-2, thus, in the second scan, we set G ' (j) = m-max {gs1 (j), gs2 (j)} = m-gs2 (j) = f ' (k ') (1)-2. If no such k exists, set each undetermined value of G to m in the second scan.

Results (English) 3:

如果G（J）不确定在第一扫描和1≤j＜＝f（k）（1）的2，因此，在第二次扫描，我们组G（J）= M max { GS1（J），GS2（J）} = M GS2（J）＝f（k）（1 - 2）。如果没有这样的K存在，集G的每个未定值M在第二次扫描
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