The center gusset plate is not crit

The center gusset plate is not critical, because its thickness (16cm) is more than the combined thickness of the two outer channel web (2x6=12cm).

(1) Solve maximum force, T
Assumed four (4) 2.5cm diameter A325-SC bolts are used

Shear Capacity
Using the AISC available shear in Table 7-3 (Group A):
ФRn = (34.6 kips/bolt)x4/2.2 = 62.91 tf 3x2.5cm
Channel C200x75 Material: ASTM A992
Double channel web thickness : 12cm total
Fu = 4.60 tf/cm^2
Fu = 4.6x2.2x2.54^2 = 65.29 ksi
Using the AISC available bearing in Table 7-4:
ФRn = (113 kips/bolt/in)x(12/25.4)x4/2.2 = 97.07 tf

(b) Based on edge distance of 5cm (2 inches approximately)
Using the AISC available bearing in Table 7-5:
ФRn = (85.9 kips/bolt/in)x(12/25.4)x4/2.2 = 73.79 tf

C200x75 Tension Capacity
Bolt hole diameter = 2.5+0.2 = 2.70 Cm
Ag = 2x[20x0.6+2x(7.5-0.6)x1.25] = 58.50 Cm^2
Ae = Anet U
The whole cross section sees tension, so the shear lag factor U = 1
Ae = [58.5-4x(0.6x2.7)]x1 = 52.02 Cm^2

Tds = ФFyAg = 0.9x3.5x58.5 = 184.28 tf
Tds = ФFuAe = 0.75x4.6x52.02 = 179.47 tf

Block Shear Rupture Capacity
Agt = 10x1.2 = 12.00
Agv = 2x(10+5)x1.2 = 36.00 Cm^2
Anv = 2x(10+5-1.5x2.7)x1.2 = 26.28 Cm^2
Ant = (10-2.7)x1.2 = 8.76 Cm^2

FuAnt = 4.6x8.76 = 40.30
0.6FuAnv = 0.6x4.6x26.28 = 72.53
Since 0.6FuAnv > FuAnt

ФRn = Ф(0.6FuAnv+UbsFuAnt)
Ubs = 1 when the tensile stress is uniform
ФRn = 0.75x(0.6x4.6x26.28+1x4.6x8.76) = 84.62 tf

ФRn = Ф(0.6FuAnv+UbsFyAgt)
ФRn = 0.75x(0.6x4.6x26.28+1x3.5x12) = 85.90 tf

The smallest ФRn from above, T = 62.91 tf

(2) Solve fillet weld size, w
Try 6mm minimum double fillet weld for 1.6cm thick gusset plate
Weld length = 35cm on each side
L/w = 350/6 = 58.33 < 100 O.K.

6mm double fillet weld capacity
ФRn = Ф(0.6xFEXX)[1+0.5x(Sinθ)^1.5](t)(L)
ФRn = 0.75x(0.6x4.9)x[1+0.5x(4/5)^1.5]x(2X0.6x0.707)x(35) = 88.90 tf > 62.91 tf O.K.

Results (Chinese Traditional) 1:

中心節點板不是關鍵，因為其厚度（16厘米）大於兩個外部管道捲筒紙（2×6 = 12厘米）的厚度。（1）解決最大的力，T 假設四4 2.5厘米直徑的A325-SC螺栓使用剪受承載力使用鞍鋼可用剪切在表7-3（A組）：ФRn=（34.6 千磅/螺栓）×4 / 2.2 = 62.91 TF <---控制承載能力（一）基於螺栓間距10厘米> 3×2 0.5厘米頻道C200x75材料：ASTM A992 雙通道腹板的厚度：12總厘米傅= 4.60 TF /平方公分傅= 4.6x2.2x2.54 ^ 2 = 65.29英寸平方鞍鋼可用軸承使用表7-4：ФRn =（113小牛皮/螺栓/中）第4 / 2.2×（12 / 25.4），X = 97.07 TF（二）基於邊緣距離的5厘米（大約2英寸）使用鞍鋼可用軸承在表7-5所示：ФRn=（85.9小牛皮/螺栓/中）第4 / 2.2×（12 / 25.4），X = 73.79 TF C200x75能力張力螺栓孔直徑= 2.5 + 0.2 = 2.70厘米的Ag = 2×[20×0.6 + X（7.5 -0.6）2 x1.25 = 58.50厘米^ 2 AE =戰神ü 整個截面看到緊張，所以剪力滯後係數U = 1 AE = [58.5-4x（0.6x2.7）1 = 52.02厘米X ^ 2 TDS =ФFyAg= 0.9x3.5x58.5 = 184.28 TF TDS =ФFuAe= 0.75x4.6x52.02 = 179.47 TF 塊剪切破裂能力的Agt = 10x1.2 = 12.00 AGV = 2×（10 + 5）×1。 2 = 36.00厘米^ 2 阿女= 2×（10 + 5-1.5 x 2.7）X1.2 = 26.28厘米^ 2 螞蟻=（10-2.7）X1.2 = 8.76厘米^ 2 FuAnt = 4.6x8.76 = 40.30 0.6FuAnv = 0.6x4.6x26.28 = 72.53 自0.6FuAnv> FuAntФRn=Ф（0.6FuAnv + UbsFuAnt）瑞銀（UBS）= 1時的拉伸應力是統一ФRn= 0.75倍（0.6x4.6x26。 28 + 1x4.6x8.76）= 84.62 TFФRn=Ф（0.6FuAnv + UbsFyAgt）ФRn= 0.75倍（0.6x4.6x26.28 + 1x3.5x12）= 85.90 TF 最小的ФRn，從T = 62.91 TF（2 ）解決角焊縫尺寸，W 試著1.6厘米厚板6最小毫米雙角的焊縫焊縫長度= 35厘米，每邊L / W =六分之三百五= 58.33 <100好嗎？6 毫米雙圓角焊縫能力ФRn=Ф（0.6xFEXX）〔1 + 0.5×（SINθ）^ 1.5]（t）的（L）ФRn= 0.75倍（0.6x4.9）×[1 + 0.5×（4/5）^ 1.5] X（2X0.6x0.707）×（35）= 88.90 TF> 62.91 TF好嗎？

Results (Chinese Traditional) 2:

中心節點板不是關鍵的，因為它的厚度（16厘米）大於兩個外槽的腹板（2×6 = 12厘米）的組合厚度。（1）求解最大的力，T 假設四（4）2.5厘米直徑A325- SC用來螺栓剪承載力表7-3（A組）使用AISC可剪：ФRn=（34.6 千磅/螺栓）×4 / 2.2 = 62.91 TF <--------控制承載力（一）基於對螺栓間距10厘米> 3x2.5cm 頻道C200x75材料：ASTM A992 雙通道腹板厚度：12共厘米：富= 4.60 TF /平方公分：富= 4.6x2.2x2.54 ^ 2 = 65.29 KSI 使用鞍鋼現有軸承表7-4：ФRn=（113 千磅/螺栓/英寸）×（12 / 25.4）×4 / 2.2 = / 25.4）×4 / 2.2 = 73.79 TF C200x75緊張運力螺栓孔直徑= 2.5 + 0.2 = 2.70厘米的銀= 2×[20x0.6 + 2×（7.5-0.6）x1.25 = 58.50平方公分AE =ANETü 整個橫截面看緊張，所以剪滯係數U = 1 AE = [58.5-4x（0.6x2.7）]×1 = 52.02平方公分TDS =ФFyAg= 0.9x3.5x58.5 = 184.28 TF TDS =ФFuAe= 0.75 x4.6x52.02 = 179.47 TF 塊剪斷能力的=的Agt = 10x1.2 12.00 AGV = 2×（10 + 5）X1.2 = 36.00厘米^ 2 ANV = 2×（10 + 5-1.5x2.7 ）X1.2 = 26.28平方公分螞蟻=（10-2.7）X1.2 = 8.76平方公分FuAnt = 4.6x8.76 = 40.30 0.6FuAnv = 0.6x4 .6x26.28 = 72.53 既然0.6FuAnv>FuAntФRn=Ф（0.6 FuAnv + UbsFuAnt）瑞銀= 1時，拉伸應力均勻ФRn= 0.75倍（0.6x4.6x26.28 + 1x4.6x8.76）= 84.62 TFФRn=Ф（0.6FuAnv + UbsFyAgt）ФRn= 0.75倍（0.6 x4.6x26.28 + 1x3.5x12）= 85.90 TF 從上面的最小ФRn，T = / W = 6分之350 = 58.33 <100 OK6 毫米雙角焊縫能力ФRn=Ф（0.6xFEXX）[1 + 0.5X（SINθ）^ 1.5（T）的（L）ФRn= 0.75倍（0.6x4 0.9）×[1 + 0.5×（4/5）^ 1.5]×（2X0.6x0.707）×（35）= 88.90 TF> 62.91 TF行

Results (Chinese Traditional) 3:

= =（34.6磅/螺栓）X4 / 2.2 = 62.91 TF <--------控制承載力









（一）基於10厘米> 3x2.5cm
通道c200x75資料螺栓間距：ASTM A992
雙通道腹板厚度：12總
福= 4.60 TF /厘米
2
福= 4.6x2.2x2.54
2 = 65.29 KSI
使用AISC可用軸承表
7-4：ФRn=（113 磅/螺栓/在）×（12 / 25.4）/ 2.2 = 97.07×TF （二）基於邊緣的距離5厘米（2英寸左右）使用AISC可用軸承表7-5：ФRn=（85



9基普/螺栓/）×（12 / 25.4）/ 2.2 = 73.79×TF c200x75能力張力螺栓孔直徑= 2.5 0.2 = 2.70厘米銀= 2×[20x0.6 2X（7.5-0.6）x1.25 = 58.50厘米2 AE =網絡ü 整個截面上看到的緊張，囙此，剪力滯係數U = 1 AE = [58.5-4x（0.6x2.7）X1 = 52.02厘米2 TDS =Фfyag= 0.9x3.5x58.5 = 184.28 TF TDS =Фfuae= 0.75x4.6x52.02 = 179.47 TF 塊剪切破裂的能力














AGT = 10x1.2 = 12
AGV = 2×（105）X1.2 = 36厘米
2
ANV = 2×（10 5-1.5x2.7）X1.2 = 26.28厘米
2
螞蟻=（10-2.7）X1。 2 = 8.76厘米
2 原生質體融合菌株= 4.6x8.76 = 40.30 0.6fuanv = 0.6x4.6x26.28 = 72.53 自0.6fuanv>原生質體融合菌株ФRn=Ф（0.6fuanv ubsfuant）瑞銀= 1時的拉應力是均勻的伸ФRn= 0.75×（0.6x4.6x26.28 1x4.6x8.76）= 84.62 TFФRn=Ф（0.6fuanv ubsfyagt）ФRn= 0.75×（0.6x4.6x26.28 3.










5X12）= 85.90 TF 最小ФRN上，T = 62.91 / W = 350/6 = 58.33 <100行6毫米的雙角焊縫的能力ФRn=Ф（0.6xfexx）[1 0.5X（罪θ）1.5]（t）的（L）ФRn= 0.75×（0.6x4。 9）×[1 0.5X（4/5）1.5]×（2x0.6x0.707）×（35）= 88.90> 62.91 TF TF好